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3 years ago

15

What is the IQR (interquartile range)?

1 answer:

Ivanshal [37]3 years ago

4 0

Median..................

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Solve for t.<br><br>3/4t = 1/4

Vlad1618 [11]

I hope this helps you

3 0

3 years ago

Chris cut a rope into two pieces. One piece was 11.36 meters long and the other piece was 13.46 meters long. About how long was

rosijanka [135]

If you would like to know about how long was the rope before Chris cut it and you would like to round each length to the nearest tenth to estimate the total length of the original piece of rope, you can calculate this using the following steps:

11.36 meters = 11.4 meters
13.46 meters = 13.5 meters

11.4 + 13.5 = 24.9 meters

Result: The rope was 24.9 meters long (before Chris cut it) - rounded to the nearest tenth.

4 0

3 years ago

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At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 6 cubic feet per minute. The dia

Alla [95]

Answer:

$0.2122\text{ ft per min}$

Step-by-step explanation:

Let r be the radius ( in feet ) of the cone,

So, the diameter of the cone = 2 × radius = 2r feet,

∵ The diameter of the base of the cone is three times the height,

If h represents the height of the cone,

⇒ 2r = 3 × h,

⇒ $r=\frac{3h}{2}$ feet,

∵ Volume of a cone,

$V=\frac{1}{3}\pi R^2 H$

Where,

R = radius, H = height,

Thus, the volume of the given cone is,

$V=\frac{1}{3}\pi r^2 h$

$=\frac{1}{3}\pi (\frac{3h}{2})^2 h$

$=\frac{3}{4}\pi h^3$

Differentiating with respect to t ( time )

$\frac{dV}{dt}=\frac{9}{4}\pi h^2\frac{dh}{dt}$

We have,

$\frac{dV}{dt}=6\text{ cubic ft per min},h=2\text{ feet}$

$6=\frac{9}{4}\pi (2)^2 \frac{dh}{dt}$

$6=9\pi \frac{dh}{dt}$

$\implies \frac{dh}{dt}=\frac{6}{9\pi }\approx 0.2122\text{ ft per min}$

4 0

3 years ago

Simplify the ratio 13:143

dmitriy555 [2]

You have to divide to find a common number. 143/13=11 1:11

3 0

3 years ago

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What is the greatest common factor of 32 and 56

alina1380 [7]

Answer:

8

Step-by-step explanation:

List the factors of each number

The factors of 32 are: 1, 2, 4, 8, 16, 32

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

Separate and find the GCF

Then the greatest common factor is 8.

Thanks for letting me help!!

4 0

2 years ago

Read 2 more answers