Estimate the square root of the imperfect square of 18.
1 answer:
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Answer:
I'll do the first one and lets see if that helps
Step-by-step explanation:
<u>Complete question:</u>
Refer the attached diagram
<u>Answer:</u>
In reference to the attached figure, (-∞, 2) is the value where (f-g) (x) negative.
<u>Step-by-step explanation:</u>
From the attached figure, it shows that given data:
f (x) = x – 3
g (x) = - 0.5 x
To Find: At what interval the value of (f-g) (x) negative
So, first we need to calculate the (f-g) (x)
(f – g ) (x) = f (x) – g (x) = x-3 - (- 0.5 x)
⇒ (f - g) (x) =1.5 x - 3
Now we are supposed to find the interval for which (f-g) (x) is negative.
⇒ (f - g) (x) = x - 3+ 0.5 x = 1.5 x – 3 < 0
⇒ 1.5 x – 3 < 0
⇒ 1.5 x < 3
⇒
⇒ x < 2
Thus for (f - g) (x) negative x must be less than 2. Thereby, the interval is (-∞, 2). Function is negative when graph line lies below the x - axis.
