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3 years ago

Which statement is true about angles 3 and 6

Mathematics

1 answer:

vlada-n [284]3 years ago

8 0

Answer:

They are vertical angles.

Step-by-step explanation:

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A Baker used 7 bags of cookie-doe to make 10 cookies he used__ of a doe for each cookies- How many?

Ksivusya [100]

Answer:

I think it is 70

Step-by-step explanation:

7(10)=70

70=70

3 0

2 years ago

Read 2 more answers

HELP ASAP

AlekseyPX

We’ll subtract the exponent in the denominator from the exponent in the numerator, keeping the base the same. Cant be simplified, because the base of the expression in the numerator is y and the base of the expression in the denominator is x.

4 0

2 years ago

Express the radical using the imaginary unit, i

Kipish [7]

Answer:

7i.

Step-by-step explanation:

Note : The given expression must be $\sqrt{-49}$ .

We have to write this radical value in the imaginary value.

The given value can be rewritten as

$\sqrt{-49}=\sqrt{49\times (-1)}$

$\sqrt{-49}=\sqrt{49}\times \sqrt{-1}$ $[\because \sqrt{ab}=\sqrt{a}\sqrt{b}]$

$\sqrt{-49}=7\times i$ $[\because \sqrt{-1}=i]$

$\sqrt{-49}=7i$

Therefore, the required expression is 7i.

8 0

3 years ago

If f(x) = (x + 9 and g(x) = --6, which describes the range of (f + g)(x)?

S_A_V [24]

Given:

Consider the below figure attached with this question.

To find:

The value of $(f+g)(x)$ .

Solution:

The given functions are:

$f(x)=|x|+9$

$g(x)=-6$

Now,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=|x|+9+(-6)$

$(f+g)(x)=|x|+9-6$

$(f+g)(x)=|x|+3$

We know that,

$|x|\geq 0$

Adding 3 on both sides, we get

$|x|+3\geq 0+3$

$(f+g)(x)\geq 3$

So, $(f+g)(x)\geq 3$ for all values of x.

Hence, the correct option is A.

6 0

3 years ago

Solve the linear equation. 8x+32=1/5(25x−15)−4x

Kipish [7]

Answer: x= 5

Step-by-step explanation:

8x+32=1/5(25x−15)−4x

8x + 32 = 25x -15 - 4x - 25x -15/ 5

8x + 32 = 5x -3 - 4x

8x + 4x - 5x = -32 - 3

7x =-35

x = 35/7

x= 5

5 0

3 years ago