Answer:4
Step-by-step explanation:
log₂[log₂(√4x)] = 1
log₂2 =1
So we replace our 1 with log₂2
log₂[log₂(√4x)] = log₂2
log₂ on bothside will cancel each other.
We will be left with;
[log₂(√4x)] = 2
log = power of exponential
√4x = 2²
√4x = 4
Square bothside
(√4x)² = 4²
4X = 16
Divide bothside by 4
4x/4 = 16/4
x = 4
We use the proportion for this case the pole and the tree with their shadows has the same shape forming a right triangle.
We use the ratio of the two triangles and equate them as
h1/s1 = h2/s2
where
h1 and s1 are the height and the length of a shadow of the pole,
and the other h2 and s2 are for the tree
Identify all the given values.
5 ft / 2 ft = (h2) / 10 ft
h2 = 25 ft
Therefore the height of the tree "h2" is 25 ft.
Answer:
Answer:8: -4/7x+1 9: y=-x+1
Step-by-step explanation:
I dont knwo the rest just put into slope intercept form
<span>If you have an equilateral triangle, the median is also the altitude so - That means that if you draw altitude, it will bisect the base of the triangle and meet at two right angles. That gives you two of the measurements for the right triangle - the side (6) hypotenuse, and the base (3). You can then figure out the height using the Pythagorean as you have the a and the c for the theorem. Then you can use 1/2 base times height to find the area.
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Answer:
Step-by-step explanation:
The principal was compounded monthly. This means that it was compounded 12 times in a year. So
n = 12
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. The total amount is given as $100000.
1) When t is 1,
100000 = P(1+0.04/12)^12×1
100000 = P(1+0.0033)^12
100000 = P(1.0033)^12
P = 100000/1.04
P = $96154
2) When t is 10
100000 = P(1+0.04/12)^12×10
100000 = P(1+0.0033)^120
100000 = P(1.0033)^120
P = 100000/1.485
P = $67340
3) When t is 20
100000 = P(1+0.04/12)^12×20
100000 = P(1+0.0033)^240
100000 = P(1.0033)^240
P = 100000/2.2
P = $45455
4) When t is 30
100000 = P(1+0.04/12)^12 × 30
100000 = P(1+0.0033)^360
100000 = P(1.0033)^360
P = 100000/3.274
P = $30544
5) When t is 40
100000 = P(1+0.04/12)^12 × 40
100000 = P(1+0.0033)^480
100000 = P(1.0033)^480
P = 100000/4.862
P = $20568
6)When t is 50
100000 = P(1+0.04/12)^12 × 50
100000 = P(1+0.0033)^600
100000 = P(1.0033)^600
P = 100000/7.22
P = $13850
