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Kaylis [27]
3 years ago
12

What is the radius of a circle that has a diameter of 38

Mathematics
2 answers:
kotegsom [21]3 years ago
8 0

Answer: 19

Step-by-step explanation: 19 would be the radius for the circle because the diameter is 2 times the radius. In this case, if you multiply 19 by 2 you get a product of 38. So 19 would be the answer. Hope It Helped

Vinvika [58]3 years ago
7 0

Answer:

The radius of the circle is 19

Step-by-step explanation:

To find the radius of a circle you divide the diameter by 2.  (to find the diameter of a circle you multiply the radius by 2)

38 divided by 2 = 19

You might be interested in
Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?
Fofino [41]

Answer:

2500

Step-by-step explanation:

Let the first square number be x^2 then the next square number is (x+1)^2.

The difference between these two consecutive numbers is 99.

This implies that:

(x+1)^2-x^2=99

We expand to get:

x^2+2x+1-x^2=99

Simplify:

2x=99-1

2x=98

Divide both sides by 2

x=49

Therefore the value of the larger perfect number is

(49+1)^2=50^2=2500.

6 0
3 years ago
Sketch the graphs - 2y – 3=x​
Dominik [7]

Answer:

this should be correct try mathaway but instead of away make it way. it won't let me say the actual name

3 0
3 years ago
An angle that has a supplement also has a complement. Always, sometimes, or never?
Assoli18 [71]
So the problem ask to what could be the right choice among the three that could support the said statement in you problem that tells that an angle that has a supplement also has a complement and the best answer would be that it is ALWAYS be TRUE. I hope you are satisfied with my answer 
8 0
3 years ago
The question is given in the picture.
lorasvet [3.4K]
This is a really interesting question! One thing that we can notice right off the bat is that each of the circles has the same amount of area swept out of it - namely, the amount swept out by one of the interior angles of the hexagon. Let’s call that interior angle θ. We know that the amount of area swept out in the circle is proportional to the angle swept out - mathematically

θ/360 = a/A

Where “a” is the area swept out by θ, and A is the area of the whole circle, which, given a radius of r, is πr^2. Substituting this in, we have

θ/360 = a/(πr^2)

Solving for “a”:

a = π(r^2)θ/360

So, we have the formula for the area of one of those sectors; all we need to do now is find θ and multiply our result by 6, since we have 6 circles. We can preempt this but just multiplying both sides of the formula by 6:

6a = 6π(r^2)θ/360

Which simplifies to

6a = π(r^2)θ/60

Now, how do we find θ? Let’s look first at the exterior angles of a hexagon. Imagine if you were taking a walk around a hexagon. At each corner, you turn some angle and keep walking. You make 6 turns in all, and in the end, you find yourself right back at the same place you started; you turned 360 degrees in total. On a regular hexagon, you’d turn by the same angle at each corner, which means that each of the six turns is 360/6 = 60 degrees. Since each interior and exterior angle pair up to make 180 degrees (a straight line), we can simply subtract that exterior angle from 180 to find θ, obtaining an angle of 180 - 60 = 120 degrees.

Finally, we substitute θ into our earlier formula to find that

6a = π(r^2)120/60

Or

6a = 2πr^2

So, the area of all six sectors is 2πr^2, or the area of two circles with radii r.
5 0
3 years ago
Which transformations are needed to change the parent some function to the sine function below?
Harrizon [31]
Beginning with the function y = sin x, which would have range from -1 to 1 and period of 2pi:
Vertical compression of 1/2 compresses the range from -1/2 to 1/2
Phase shift of pi/2 to the left
Horizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4pi
Vertical shift of 1 unit up moves the range to 1/2 to 3/2
So the first choice looks like a good answer.
7 0
3 years ago
Read 2 more answers
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