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velikii [3]
3 years ago
14

- 4 ( x - 5 ) = 92 What is x?

Mathematics
2 answers:
SashulF [63]3 years ago
5 0

Answer:

x = 28

Step-by-step explanation:

4 ( − 5 ) = 9 2

4 − 2 0 + 2 0 = 9 2 + 2 0

4x =112

4x/4 = 112/4

x = 28

Stells [14]3 years ago
4 0

Answer:

Let's solve your equation step-by-step.

−4(x−5)=92

Answer:

x=−18

Step-by-step explanation:

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Jorge needs a string that is 4 feet long. so far his string is 44 inches. is it long enough or does he need to make it longer
mr Goodwill [35]
There are 12 inches in a foot. If he needs 4 feet, and 4 times 12 equals 48, then he needs 4 more inches.
3 0
3 years ago
Help please 30 points
Solnce55 [7]

Answer:

D 43.5

Step-by-step explanation:

Start with a pile of 17 and 3/4 inches.

Over 3 weeks the stack grows by 25.75 inches.

17.75 + 25.75 = 43.5

5 0
4 years ago
Read 2 more answers
Will upvote please help
Fynjy0 [20]
T = 12 min,  T o = 80° C, T s = 50 °C,  T ( 12 ) = 60° C
60 = 50 + ( 80 - 50 ) · e^(-12k)
10 = 30 · e^(-12k)
e^(-12k) = 0.3333...
ln ( 0.333.. ) = - 12 k
- 12 k = - 1.1
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4 0
3 years ago
Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
4 years ago
A business owner collected data on the people working for her company. She determined the average number of minutes each employe
Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.<em> </em>

Step-by-step explanation:

The following information is missing

<em>A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.  </em>

<em>A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.  </em>

<em>The business owner uses the median and IQR to determine the center and variability of the data sets. Which best describes the comparison? </em>

<em>The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric. </em>

<em>The comparison would be more accurate using the mean and MAD because the median of both data sets is the same. </em>

<em>The comparison using median and IQR is best because one of the graphs is not symmetrical. </em>

<em>The comparison using median and IQR is best because the median is greater than the IQR for both data sets.</em>

<em />

Mean and MAD are useful for comparison when both data sets are symmetrical.

In the women box plot the Q1 is at 34, the median is at 48, and the Q3 is at 50, so it is not symmetrical (the difference between the median and the Q1, and the Q3 and the median is not the same)

8 0
4 years ago
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