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d1i1m1o1n [39]
3 years ago
5

How do I find side b?

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0

Answer:

u use cosine

and then some proportion

i am 60% sure

dont trust me

i learned this a week ago and now i forget it all help me study for the quiz i have on this tmrw?

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Let f(x) = 1/x . Find the number b such that the average rate of change of f on the interval [2, b] is − 1/8
vekshin1

Answer:

b=4

Step-by-step explanation:

So, we have the function f(x)=1/x. We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

f(2) = 1/(2) = 1/2

So, we have the point (2, 1/2)

At point b, f(b) = 1/b.

Let's plug this into the slope formula:

\frac{y_2-y_1}{x_2-x_1}=\frac{.5-\frac{1}{b} }{2-b}  =-1/8

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

\frac{.5b-1}{2b-b^2} =\frac{-1}{8}

Now, cross multiply.

4b-8=b^2-2b

b^2-6b+8=0

Solve for b. Factor using the numbers -4 and -2.

=(b-4)(b-2)=0

Thus, b=4 or b=2.

However, b=2 is not a possible solution since the interval [2,2] means nothing. Thus, b=4.

4 0
3 years ago
A math club has 40 members. The number of girls is 5 less than 2 times the number of boys. How many members are boys? How many m
scZoUnD [109]
15 girls and 25 boys

5 0
3 years ago
How do you work these types of problems out?
vitfil [10]

Answer:

3,000 kg (3.14)+1.5m^3  and that is math!

Step-by-step explanation:

5 0
3 years ago
The price of a burger went from $6.00 to $8.00. What is the percent of change? This is increase and decrease
Lubov Fominskaja [6]
The cost of the burger went up 2%/ and you can also subtract 6 from8 and get the answer. Thank you have a nice day
7 0
3 years ago
Which of the following is the best estimate of 7/8? ( Answer ASAP )
Triss [41]

Answer:

C

Step-by-step explanation:

just round up to nearest number and 7/8 is 0.87 so it coloser to 1 than half and the others are way to big.

6 0
3 years ago
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