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2 years ago

I needs help please, a step by step answer

Mathematics

2 answers:

trapecia [35]2 years ago

6 0

Answer:

Step-by-step explanation:

Pythagorean theorem: a²+b²=c² a²=32² b²=60² c²=hypotenuse²

32²+60²=c²

1024+3600= c²

4624=c²

Now, take the square root of both sides of the equation to find c

$\sqrt{4624}$ =c

68=c

Paladinen [302]2 years ago

6 0

The answer to this question is 68.

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saul85 [17]

The answer to this question is A). 39 b). 56

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3 years ago

What is the value of a? -2(a-8)+6a=36

Aleksandr [31]

First we expand the brackets:

-2a + 8 + 6a = 36
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4a = 28

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3 years ago

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If my dog was born 4 weeks before August 27th how old will my dog be

Elenna [48]

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Step-by-step explanation:

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2 years ago

Which symbol correctly compares these two fractions?<br> 4/7 and 8/16

WITCHER [35]

Answer: 4/7 > 8/16

Step-by-step explanation:

Draw each fraction on a fraction bar (similar to a Hersey's Bar each fraction bar being the same length just broken up differently to represent each fraction) and you will see that 4/7 is bigger than 8/16.

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3 years ago

Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?

allsm [11]

Answer:

1. No.

$f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1$

Since f(1)=f(3) and $1\neq 3$ then f isn't one-to-one.

2. No

$f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

3. No

$0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

4. Yes

$0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8}; \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8}; \text{then } f(3)=1$

Since $f(0)\neq f(1)\neq f(2) \neq f(3)$ , then f is one-to-one

5. Since f(1)=f(3) and $1\neq 3$ then, f isn't one-to-one

3 0

3 years ago