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Liono4ka [1.6K]
3 years ago
5

You have a slice cut from a perfectly round pizza. The perimeter of your slice is 10 inches. What is the largest area that it ca

n possibly have?
Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer: See explanation

Step-by-step explanation:

A pizza is in the shape of a circle.

Since the perimeter is 10 inches, we have to find the radius. This will be:

2πr = 10

πr = 10/2

πr = 5

3.14r = 5

r = 5/3.14

r = 1.5924

Area = πr²

= 3.14 × 1.5924²

= 7.96 inches

= 8 inches approximately

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Answer:   0.93 radians & 2.21 radians

<u>Step-by-step explanation:</u>

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An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 150 lb and
charle [14.2K]

Answer:

A) 0.5737

B) 0.9884

Step-by-step explanation:

We are given that an engineer is going to redesign an ejection seat for an airplane.  The new population of pilots has normally distributed weights with a mean of 160 lb and a standard deviation of 27.5 lb i.e.;                                                 \mu = 160 lb  and \sigma = 27.5 lb

(A) We know that Z = \frac{X - \mu}{\sigma} ~ N(0,1)

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If a pilot is randomly selected, the probability that his weight is between 150 lb and 201 lb = P(150 < X < 201)

P(150 < X < 201) = P(X < 201) - P(X <= 150)

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Therefore, P(150 < X < 201) = 0.9319 - 0.3582 = 0.5737 .

(B) We know that for sampling mean distribution;

            Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

If 39 different pilots are randomly selected, the probability that their mean weight is between 150 lb and 201 lb is given by P(150 < X bar < 210);

 P(150 < X bar < 210) = P(X bar < 201) - P(X bar <= 150)

  P(X bar < 201) = P( \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{201 - 160}{\frac{27.5}{\sqrt{39} } } ) = P(Z < 9.311) = 1 - P(Z >= 9.311)

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Therefore,  P(150 < X bar < 210) = 0.999995 - 0.0116 = 0.9884

C) If the tolerance level is very high to accommodate an individual pilot then it should be appropriate ton consider the large sample i.e. Part B probability is more relevant in that case.

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-18-11-7

A really easy way is to add all of it together and then slap a "-" sign in front.

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<u></u>

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