Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
Answer:
Start at postive 1 on the y axis put a dot there. From the dot go down 6 and go left 5.
Step-by-step explanation:
6/5=rise over run
1=y-axis
y=mx+b
m=slope
b=y-intersept
Answer:
1.792
Step-by-step explanation:
(24,215-23,500)/[3678/sqrt(85)]
715/[3678/sqrt(85)]
715/398.94
1.792
Please give me brainliest :)
