The answer would be C.) The way you group numbers in a series of multiplication problems doesn't change the final product.
A. is invalid because any whole number x 1 would be that whole number as the product.
B. Is invalid because any number x 0 will be 0.
D. is invalid because you can multiply in any way as long as the number's value (example, 1 turning into -1 without any multiplication of -1) does not change during the process.
<h3>
Answer: 9/38</h3>
Reason:
There are 10 red cards out of 10+10 = 20 total.
10/20 = 1/2 is the probability of selecting a red card.
If the red card is not put back (i.e. "no replacement"), then the chances of getting another red card is (10-1)/(20-1) = 9/19
Multiply the two fractions mentioned to get the final answer.
(1/2)*(9/19) = (1*9)/(2*19) = 9/38
N/3= -12.
You want to get "N" by itself. On one side of the equation, with no other number. To do this, we do the opposite of what we have next to the letter "N"
In this case, N is being divided by 3, and the opposite of dividing is multiplying.
So you need to multiply both sides by 3.
The 3's on the left side cancel out, leaving N by itself.
Now you have N= -12 * 3
-12 * 3 = -36
So N = -36
36/4 = 9 Kai counts 9 times
36/6 = 6 Taya counts 6 times
Taya counts less
Kai's statement is incorrect.