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VLD [36.1K]
3 years ago
8

Write an equation for the line that has a slope of 1/2 and passes though the point (-2,5)?

Mathematics
2 answers:
IgorC [24]3 years ago
7 0

Answer: y = 1/2x + 6

Step-by-step explanation:

b = y1 - m • x1

Plug everything in:

b = 5 - (1/2) • -2

= 6

Written in y = mx + b is:

y = 1/2x + 6

Schach [20]3 years ago
5 0

Answer:

y=1/2x+6

Step-by-step explanation:

Y=MX+B

m= slope=1/2

b= y-intercept

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In a survey of 269 college students, it is found that
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Answer: a) 83, b) 28, c) 14, d) 28.

Step-by-step explanation:

Since we have given that

n(B) = 69

n(Br)=90

n(C)=59

n(B∩Br)=28

n(B∩C)=20

n(Br∩C)=24

n(B∩Br∩C)=10

a) How many of the 269 college students do not like any of these three vegetables?

n(B∪Br∪C)=n(B)+n(Br)+n(C)-n(B∩Br)-n(B∩C)-n(Br∩C)+n(B∩Br∩C)

n(B∪Br∪C)=69+90+59-28-20-24+10=156

So, n(B∪Br∪C)'=269-n(B∪Br∪C)=269-156=83

b) How many like broccoli only?

n(only Br)=n(Br) -(n(B∩Br)+n(Br∩C)+n(B∩Br∩C))

n(only Br)=90-(28+24+10)=28

c) How many like broccoli AND cauliflower but not Brussels sprouts?

n(Br∩C-B)=n(Br∩C)-n(B∩Br∩C)

n(Br∩C-B)=24-10=14

d) How many like neither Brussels sprouts nor cauliflower?

n(B'∪C')=n(only Br)= 28

Hence, a) 83, b) 28, c) 14, d) 28.

4 0
3 years ago
Use undetermined coefficients to find the particular solution to 7t + 5=y''+y'-4y У, (t) - Preview Get help: Video Points possib
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Suppose y_p=a_0+a_1t is a solution to the ODE. Then {y_p}'=a_1 and {y_p}''=0, and substituting these into the ODE gives

a_1-4(a_0+a_1t)=7t+5\implies\begin{cases}-4a_1=7\\-4a_0+a_1=5\end{cases}\implies a_0=-\dfrac{27}{16},a_1=-\dfrac74

Then the particular solution to the ODE is

y_p=-\dfrac{27}{16}-\dfrac74t

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Factor the Expression. 8x - 40 *<br> (8x - 5)<br> 8(x - 5)<br> 8(x - 40)
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Answer:

Step-by-step explanation:

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3 years ago
Find hcf of x³y and x⁴y³<br>no a and d ​
Ierofanga [76]

Answer:

See solutions below

Step-by-step explanation:

a) Given the expressions

x³y and x⁴y³

Find their factors

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x⁴y³ = (x * x * x * y) * x * y * y

GCF = x*x*x*y

GCF = x³y

The expressions in parenthesis is the GCF. Hence the GCF of x³y and x⁴y³ is x³y

b) For 48m⁶n⁵p⁴ and 20m⁴n⁵p⁶

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20m⁴n⁵p⁶ = 5 * (4 * m⁴ * n⁵ * p⁴) * p²  

GCF is the expression common to both terms

GCF = 4 * m⁴ * n⁵ * p⁴

GCF = 4m⁴n⁵p⁴

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