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AnnyKZ [126]
3 years ago
12

PLEASE HELP!!! I WILL GIVE BRAINLIEST!!! Explain how to use estimation to help find the product of two decimals. Give an example

with both estimated and actual answers.
Mathematics
2 answers:
san4es73 [151]3 years ago
6 0
You can use estimation to find the product of two decimals by rounding both the decimal’s so the nearest tenth or tens place (depending on how long it is) and then multiplying the decimals.

for example, if you had 4.6 and 8.9, you have to round the 4.6 and 8.9. you round the 4.6 up to 5 because the 6 bumps the 4 up to 5) and then round 8.9 to 9 (because the 9 bumps the 8 up to 8.) then, multiply 5 and 9 and you get 45!
Nastasia [14]3 years ago
4 0
Here’s an example , say you were given 8.45 , & 4.55 , first you’d round them both up (since the decimal place is above 5) , meaning 8.45 would go to 8.5 & 4.55 would go to 4.6, so if you’re adding it & you’re trying to find estimated , estimated would be 13.1 , the actual answer would be 13
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Answer:

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Step-by-step explanation:

The equation is already correct, you just want to get x as a number that would increase the value.

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3 years ago
Convert from Decimal Notation to Scientific Notation
Brrunno [24]

Answer:

Hence, 87,50,000 can be expressed as $8.75 \times 10^{6}$.

Step-by-step explanation:

- Given 87,50,000

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Step 1 of 1

Consider 87,50,000.

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2 years ago
According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

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