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photoshop1234 [79]
4 years ago
5

Indentify the radical expression of

{1/3} " alt="5{}^{1/3} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Nat2105 [25]4 years ago
8 0

Answer:

D. cube root of 5

Step-by-step explanation:

5^(1/3) = cube root of 5^1

answer is D. cube root of 5

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A fair coin is tossed repeatedly with results Y0, Y1, Y2, . . . that are 0 or 1 with probability 1/2 each. For n ≥ 1 let Xn = Yn
Gekata [30.6K]

Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i) for all i,i',j and for X_n in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that j=2, i=1, i'=0 then we have this:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}

Because we can only have j=2, i=1, i'=0 if we have this:

Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0, from definition given X_n = Y_n + Y_{n-1}

With i=1, i'=0 we have that Y_n =1 , Y_{n-1}=0, Y_{n-2}=0

So based on these conditions Y_{n+1} would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that j=2, i=1, i'=2 for this case in order to satisfy the definition then Y_n =0, Y_{n-1}=1, Y_{n-2}=1

But on this case that means X_{n+1}\neq 2 and on this case the probability P(X_{n+1}=j| X_n =i, X_{n-1}=i')= 0, so we have a counter example and we have that:

P(X_{n+1} =j| X_n =i, X_{n-1}=i') \neq P(X_{n+1} =j | X_n =i) for all i,i', j so then we can conclude that we don't have a Markov chain for this case.

6 0
3 years ago
I don't understand (t+8)(-2)=12
Evgen [1.6K]
It it called an equation. Equation consist of number, symbols, and a equal sign.
To solve, first do -2 times t and -2 times 8. Your equation would look like this after: -2T+(-16)=12. Then add 16 to each side. -2T=28. Next, divide by -2. T=-14 is your answer.
5 0
3 years ago
What is 64% of 680kg
Anuta_ua [19.1K]

Answer:

435.2kg (1DP)

Step-by-step explanation:

0.64x680

64 divided by 100 = 0.64

4 0
3 years ago
Read 2 more answers
Set of data with 350,000 numbers is normally
Rudiy27

Step-by-step explanation:

given a normal distribution with the given parameters the probability (= the % of the area of the distribution curve) for a number to be between 203 and 1803 is

0.9987

so, 99.87% of all numbers are expected to be in that range.

for 350,000 numbers that means

350,000×0.9987 = 349,545 numbers are expected to be between 203 and 1803.

7 0
2 years ago
Is there any tutors orrr
Papessa [141]
There’s tutors for math i just asked a tutor for help lol
4 0
3 years ago
Read 2 more answers
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