Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150
For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)
Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150
Your answer is 98. Is there a multiple choice?
Answer:
(-8,-3)
(-4,-1)
(0,1)
(2,2)
(6,4)
Step-by-step explanation:
One by one, substitue the x values and solve for y
Answer: 3.14159 pie
Step-by-step explanation:
no the actual answer just being goofy
The first odd number is 1. The next is 2 more than the previous one.
It's an arithmetic sequence.
The general term of an arithmetic sequence:

a_n - n-th term
a_1 - first term
d - common difference.
We have

Substitute:

<h3>Answer: 137th odd number is equal 273.</h3>