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vodomira [7]
3 years ago
6

3 x 10 + 2 x 1 + 6 x 1/100 +4 x 1/1000 is the expanded form of which decimal?

Mathematics
1 answer:
lukranit [14]3 years ago
7 0

Answer:

32.064

Step-by-step explanation:

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N+12=18.2
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N=6.2
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What is your favorite color? A larger survey of countries, including the United States, China, Russia, France, Turkey, Kenya, an
prohojiy [21]

Answer:

z=\frac{0.253 -0.24}{\sqrt{\frac{0.24(1-0.24)}{75}}}=0.264  

p_v =2*P(z>0.264)=0.792  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of students said that blue is their favorite color is not different from 0.24

Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

X=19 represent the students said that blue is their favorite color

\hat p=\frac{19}{75}=0.253 estimated proportion of  students said that blue is their favorite color

p_o=0.24 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is different from 0.24.:  

Null hypothesis:p=0.24  

Alternative hypothesis:p \neq 0.24  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.253 -0.24}{\sqrt{\frac{0.24(1-0.24)}{75}}}=0.264  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>0.264)=0.792  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of students said that blue is their favorite color is not different from 0.24

7 0
3 years ago
The length of human pregnancies from conception to birth varies according to a distribution that is approximately Normal with a
Naya [18.7K]

Answer:

P(X<240)=0.0521

P(240<X<270)=0.5466

280 days

Step-by-step explanation:

we are given the following information

mean=μ=266 days

standard deviation=σ=16 days

P(X<240)=P(X-μ/σ<240-266/16)=P(z<-1.625)

This probability can either be determined by utilizing normal distribution table or using Excel.

Using Excel function <em>NORM.S.DIST(-1.625,TRUE)</em> we get

P(X<240)=0.0521

P(240<X<270)=P((240-266)/16<X-μ/σ<(270-266)/16)=P(-1.625<z<0.25)

P(-1.625<z<0.25)=P(z<0.25)-P(z<-1625)

Using Excel function

<em>NORM.DIST(270,266,16,TRUE)-NORM.DIST(240,266,16,TRUE)</em> we get

P(240<X<270)=0.5466

P(X>x)=0.20

P(z>(x-266)/16)=0.20

Using Excel function <em>NORM.INV(0.8,266,16)</em> we get

x=280

<em>OR</em>

P(X>x)=0.2

The area to the right of x is 0.2 and the area between mean and x is

0.5-0.2=0.3

Looking for 0.3 in the normal distribution table we don't find 0.3 but the closest value is .3023 and it corresponds to z-value 0.85.

z=0.85

z=x-μ/σ

σ*z+μ=x

x=16*0.85+266

x=279.6≅280

The longest 20% of pregnancies lasts 280 days

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Colton scored a 70 on his first history test of the term and a 91 on the second history test. By what percent did Colton's score
Ilya [14]

Answer:

20%

Step-by-step explanation:

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3 years ago
7.54×10³ im so stuck
LekaFEV [45]

Answer:

7540

Step-by-step explanation:

10 raised to the power of 3 is 1000

7.54 * 1000 = 7540

3 0
3 years ago
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