The answer is 4. The mean is 4 beacuse thats what you multiply ... and yeah
Assume that each of the 6 numbers has an equal probability of showing up for each die.
The probability of obtaining a six from the red die is 1/6, or
P(6 from the red die) = 1/6.
Similarly,
P(6 from the green die) = 1/6.
The tossing of the red die, followed by the tossing of the green die are independent events. Therefore
P(6 from the red die AND 6 from the green die) = (1/6)*(1/6) = 1/36.
Answer: 1/36
Step-by-step explanation:
55x+6=120
55x=120-6
55x=114
X=114/55
Your answer would be -624 because 1-210-3= -212 then 3 times -212 +12= -624
Answer:
The initial population was 2810
The bacterial population after 5 hours will be 92335548
Step-by-step explanation:
The bacterial population growth formula is:

where P is the population after time t,
is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours
Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:





Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:



Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

