Given

subject to the constraint

Let

.
The gradient vectors of

and

are:

and

By Lagrange's theorem, there is a number

, such that


It can be seen that

has local extreme values at the given region.
1.) 58
2.) 205
3.) 134
4.) 150
5.) 21
6.) 670
7.) 33
8.) 50/7 or 7 1/7
9.) 42
These are all your answers
Answer:
Percent Change Formula: [(new - old)/old] * 100
Step-by-step explanation:
New - old
80 - 20 = 60
Difference between new - old divided by old
60/20 = 3
Previous quotient times 100
3*100 = 300
Percent Change is 300%
Check your answer
300% of 20 is 60
20 + 60 = 80
In the half-angle formula for sine and cosine, notice that a plus/minus sign appears in front of each radical (square root). Whether your answer is positive or negative depends on which quadrant the new angle (the half angle) is in
Answer:
10x²−9x
Step-by-step explanation:
10x²−10x−6+x+6
=10x²−10x−6+x+6
Combine Like Terms:
=10x²−10x−6+x+6
=(10x²)+(−10x+x)+(−6+6)
=10x²−9x
Hope this helps!