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kondaur [170]
2 years ago
15

-1/6 x -2 1/10 = ? help ya girl out

Mathematics
2 answers:
Nataly_w [17]2 years ago
5 0

Answer:

the answer is r (‑1)/​(6*​x)-​2.1

Step-by-step explanation:

Galina-37 [17]2 years ago
5 0
You multiply -1/6 by -2 to get positive 1/3and are you adding or multiplying or What the 1/10
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A room is in the shape of a cube with 6.2-foot edge lengths.
Veronika [31]
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Given information
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It is a cube
Length = 6.2 ft

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Find one surface
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6.2 x 6.2 = 38.44 ft²

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Find all 6 surfaces
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38.44 x 6 = 230.64 ft²

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Answer: 230.64 ft²
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3 0
3 years ago
HELP PLEASE I NEED THIS DONE ASAP
Nata [24]

a). 0.45 with a line over the 45 means 0.45454545454545... forever.

It's equivalent to  45/99  which is  <em>5/11</em> .

b). 0.45 with a line over the 5 means 0.455555555... forever.

It's equivalent to (0.4 + 0.555555.../10)

The 0.4 part is  4/10

The 0.5555555555.../10 part is  5/90 .

(4/10) + (5/90) = <em>41/90 </em>

c). 0.45 means 45/100 .  That's <em> 9/20</em> .

I don't think you're supposed to be posting unit test questions on Brainly.

6 0
3 years ago
The graph of quadratic function p is shown on the grid. (-3, 3) (3, 3) If (x) = x and p(x) = 5(x) + n, what is the value of n?​
aliina [53]

Answer:

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
8(19-17) number- number
STatiana [176]

Answer:

16

Step-by-step explanation:

8(19-17)=8(2)=16

7 0
3 years ago
A computer maker receives parts from three suppliers, S1, S2, and S3. Fifty percent come from S1, twenty percent from S2, and th
rewona [7]

Answer:

a) 4.9 % of all parts is defective or 0.049 of the total parts.

b)  0.5102 is the probability that the defective part was supplied by S1

Step-by-step explanation:

N is the total number of parts from supplier S1, S2 and S3.

N1 = 0.5*N is the total number of part supplied by S1

N2 = 0.2*N is the total number of part supplied by S2  

N3 = 0.3*N is the total number of part supplied by S3

a) if Nd1 is the number of defective parts from supplier S1, Nd2 is the number of defective parts from supplier S2 and Nd3 is the number of defective parts from supplier S3, the the total defective parts Nd is:

Nd = Nd1 + Nd2 + Nd3, where

Nd1 = 0.05*N1 = 0.05*0.5*N = 0.025*N,

Nd2 = 0.03*N2 = 0.03*0.2*N = 0.006*N,

Nd3 = 0.06*N3 = 0.06*0.3*N = 0.018*N,

Then Nd = Nd1 + Nd2 + Nd3 =  0.049*N, so Nd/N = 0.049

b) P(S1 \vert d) = \frac{P(S1,d)}{P(d)} = \frac{P(d \vert S1)}{P(d)} = \frac{0.05*0.5}{0.049} \approx 0.5102

for the last expression I used the Bayes tehorem.

P(S1 \vert d) is the probability that occur S1 given that d (defective) is true. This a conditional probability.

see at https://en.wikipedia.org/wiki/Bayes%27_theorem

6 0
3 years ago
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