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Svet_ta [14]
3 years ago
6

Question 3 of 10

Mathematics
1 answer:
Aleks [24]3 years ago
4 0
C=+3 since your adding three more onto four
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-3+2b>8 what is the solution
Rzqust [24]

Answer:b>42

Step-by-step explanation:

2b>81+3

2b>84

3 0
3 years ago
PLEASE HELPPPPPP. I NEED IT DONEEEEE. ​
agasfer [191]

<u><em>Answer:</em></u>

1. Couples tickets: $8

   Individual tickets: $4

2. Song download cost: $2

    Movie download cost: $15

<u><em>Step-by-step explanation:</em></u>

You can solve both of these questions by doing system of equations.

Let's start with question 1.

There are 2 variables in this equation:

- Couples tickets price: let's represent these with the letter C

- Individual tickets price: let's represent these with the letter K

Writing the two equations would look this these:

5c + 2k = 48

3c + 2k = 32

Next, isolate a variable. I am going to isolate K in the first equation.

2k = -5c + 48 \\k = -\frac{5}{2}c + 24

Now that we isolated a variable we can plug that back in to the second equation:

3c + 2(-\frac{5}{2}c + 24) = 32\\3c - \frac{10}{2}c + 48 = 32\\3c -5c + 48 = 32\\-2c + 48 = 32\\-2c = -16\\c = 8

We found that c is equal to 8 so we can put that back in to an equation to solve for k.

5(8) + 2k = 48

40 + 2k = 48

2k = 8

k = 4

Therefore, the price for couples tickets is $8 and the price for individual tickets is $4.

<u><em>Check #1:</em></u>

5(8) + 2(4) = 48

40 + 8 = 48

48 = 48

3(8) + 2(4) = 32

24 + 8 = 32

32 + 32

Now, let's go on to question 2.

There are 2 variables in this equation:

- Price of songs downloaded: let's represent these with S

- Price of movies downloaded: let's represent these with M

Writing the two equations would look like this:

15s + 11m = 195

15s + 8m = 150

There is a simple way to answer this system, however.

If you change the bottom equations signs to negative you can minus the second equation from the first equation like this:

15s + 11m = 195

-(15s +8m = 150)

Minus them to get this equation:

3m = 45

Solve

m = 15

We have found that each movie download costs $15, now let's plug this back into an equation:

15s + 11(15) = 195

15s + 165 = 195

15s = 30

s = 2

Each song costs $2 to download.

<em><u>Check #2:</u></em>

15(2) + 11(15) = 195

30 + 165 = 195

195 = 195

15(2) + 8(15) = 150

30 + 120 = 150

150 = 150

<em>I hope this helps!!</em>

<em>- Kay :)</em>

6 0
3 years ago
Someone, please help me fill this out
nadezda [96]

Answer:

Here is the summary:

  • y = 13x+5 satisfies the points (0, 5) and (-2, -21)
  • y = -3x satisfies the points (0, 0), (-5, -15) and (-3, 9)
  • y = x-10 satisfies the points (8, -2)

Step-by-step explanation:

Given the equation

  • y = 13x+5
  • y = -3x
  • y = x-10

The points which satisfy the equation y=13x+5

y = 13x+5

Checking the point (0, 5)

5 = 13(0)+5

5 = 0 + 5

5 = 5

TRUE

Checking the point (-2, -21)

-21 = 13(-2)+5

-21 = -26 + 5

-21 = -21

TRUE

The points which satisfy the equation y=-3x

y = -3x

Checking the point (0, 0)

0 = -3(0)

0 = 0

TRUE

Checking the point (-5, -15)

y = -3x

-15 = -3(-5)

-15 = -15

TRUE

Checking the point (-3, 9)

y = -3x

9 = -3(-3)

9 = 9

TRUE

The points which satisfy the equation y=x-10

y = x-10

Checking (8, -2)

-2 = 8 - 10

-2 = -2

TRUE

Therefore, from the above calculations we conclude the summary:

Here is the summary:

  • y = 13x+5 satisfies the points (0, 5) and (-2, -21)
  • y = -3x satisfies the points (0, 0), (-5, -15) and (-3, 9)
  • y = x-10 satisfies the points (8, -2)
7 0
3 years ago
What is the equation of the following line?
ratelena [41]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
What is the factored form of 64g^3+8
vivado [14]
\bf \textit{difference and sum of cubes}&#10;\\\\&#10;a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad&#10;(a+b)(a^2-ab+b^2)= a^3+b^3 &#10;\\\\&#10;a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad&#10;(a-b)(a^2+ab+b^2)= a^3-b^3\\\\&#10;-------------------------------\\\\&#10;64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3&#10;\\\\\\&#10;(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]&#10;\\\\\\&#10;(4g+2)(16g^2-8g+4)
3 0
3 years ago
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