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gregori [183]
3 years ago
13

In Oregon, the mean annual rainfall in Rockaway Beach is 118.88 inches and the mean annual rainfall in Falls City is 122.28 inch

es. Which conclusion can you make using this information?
Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0

Answer:

Step-by-step explanation:

Based on this information, you could conclude that the annual rainfall in Falls City is generally more than that of the annual rainfall in Rockaway Beach. This is based on the information provided since the numbers given are the mean annual rainfall. Meaning that this is the average amount of rain that falls in any given year in that specific location. Since the amount provided for Falls City is a larger number then it means it gets more rainfall than Rockaway Beach on average and would therefore be the safest conclusion that can be made.

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Ne4ueva [31]
<h2><u>Answer with explanation</u>:</h2>

Let p be the population proportion of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

Set of hypothesis :

H_0: p=0.43\\\\ H_a:p\neq0.43

Confidence interval for population proportion is given by :-

\hat{p}\pm z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}} , where

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and z_c is the two-tailed z-value for confidence level (c).

As per given ,

Sample size of parents : n= 1085

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Sample proportion :  \hat{p}=\dfrac{466}{1085}\approx0.429

Critical value for 90​% confidence interval : z_c=1.645  ( by z-value table)

Now, the  90​% confidence interval :

0.429\pm (1.645)\sqrt{\dfrac{0.429(1-0.429)}{1085}}\\\\=0.429\pm 0.0247\\\\=(0.429-0.0247,\ 0.429+0.0247)\\\\=(0.4043,\ 0.4537)

Thus , the 90​% confidence interval: (0.4043, 0.4537).

Since 0.43 lies in 90​% confidence interval , it means we do not  have enough evidence to reject the null hypothesis .

i.e. We are have no evidence that parents' attitudes toward the quality of education have changed.

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Step-by-step explanation:

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Step-by-step explanation:

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