Part (a)
The picture alone, without the frame, is 16 by 20
When accounting for the frame, the larger rectangle is 16+2x by 20+2x
We add up all four sides to get the perimeter
(16+2x)+(20+2x)+(16+2x)+(20+2x)
8x+72
or you can use this perimeter of a rectangle formula
P = 2(L+W)
P = 2(20+2x+16+2x)
P = 2(4x+36)
P = 8x+72
Answer: 8x+72
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Part (b)
Multiply the length and width to find the area of the rectangle.
area = length*width
A = L*W
A = (20+2x)*(16+2x)
A = 20(16+2x) + 2x(16+2x)
A = 320+40x + 32x + 4x^2
A = 4x^2 + 72x + 320
Answer: 4x^2 + 72x + 320
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Part (c)
Plug x = 2 into the perimeter equation found in part (a)
P = 8x+72
P = 8*2+72
P = 16+72
P = 88
Now plug x = 2 into the area equation found in part (b)
A = 4x^2 + 72x + 320
A = 4(2)^2 + 72(2) + 320
A = 4(4) + 72(2) + 320
A = 16 + 144 + 320
A = 160+320
A = 480
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Answers:
Perimeter = 88 inches
Area = 480 square inches
Check the picture below.
a rhombus is a quadrilateral with all equal sides.
now, the sides do not have to be slanted, but they must be equal, IF it happens that all sides meet at right-angles, then the rhombus is a "rectangle", due to its right-angleness, incidentally enough, since all sides are equal, if that ever happens, it also becomes a square.
This is an example of a composite function which can be simplified to g(fx). Literally input f(x) into the x of g(x), leading to the answer of 80x^2-120x+42
Answer:
1,2,3,6
Step-by-step explanation:
6x1, 2x3, 3x2, 6x1
i study hard and work my hardest
The number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways
<h3>How to calculate the permutation</h3>
The formula for permutation is given as;
Permutation = 
n = 16
r =4
Permutation = 
Permutation = 
Permutation = 43, 680 ways
Thus, the number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways
Learn more about permutation here:
brainly.com/question/12468032
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