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Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
Answer:
Step-by-step explanation:
Given that latitude and longitude describe locations on the Earth with respect to the equator and prime meridian.
Latitude High Temp
("N)
12 53
16 41
30 67
36 63
32 70
11 58
10 61
33 67
30 72
Slope 0.732
Int -21.56266667
Regression line is y = 0.732x-21.563 where x represents the latitude and y high temperature
Since slope = 0.732, we get temp increases by 0.8 degree for 1 degree increasenorth in latitude
Hence option c is right
Answer:
62390
Step-by-step explanation:
you have to round up if it's 5 or more and round down if it's less.
Answer:
Kerri
calculate z scores z= (x - xbar)/stdev
Kerri = 1.7
Cade = .7
Vincent = 1
Step-by-step explanation:
