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aksik [14]
3 years ago
10

Calculate the power in kilowats required to lift a 500 kg mass 12 meters in one second

Mathematics
1 answer:
Anon25 [30]3 years ago
5 0
I think that the answer is 58,800 watts
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Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2

For absolute minimum we take the minimum values of x and y.

x_{minimum} =1\\y_{minimum}=1\\

Plugging in the minimum values in the function.

g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\

Absolute minimum value will be always positive.

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For absolute maximum we take the maximum values of x and y.

x_{maximum} =2\\y_{maximum}=2\\

Plugging in the maximum values in the function.

g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

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