Calculate the power in kilowats required to lift a 500 kg mass 12 meters in one second
1 answer:
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Answer:
- a=1
- b=1
- c=-4
- x = (-1 ±√17)/2
Step-by-step explanation:
The coefficient of x^2 is "a". That is 1.
The coefficient of x is "b". That is 1.
The constant term is "c". That is -4.
The values of a, b, and c are 1, 1, and -4, respectively.
_____
The solution is ...
x = (-b ±√(b^2-4ac))/(2a)
Filling in the values of a, b, and c, this is ...
x = (-1 ±√(1^2 -4·1·(-4)))/(2·1)
x = (-1 ±√17)/2
