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3 years ago

Georgia. 0.029 can be written as 29 / 100 is he correct

Mathematics

2 answers:

bija089 [108]3 years ago

7 0

Yes because if you write it it's twenty nine out of one hundred

Vera_Pavlovna [14]3 years ago

4 0

No, its wrong 29/100= 0.29
BUT... 29/1000 equals 0.028 :)

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3 years ago

Read 2 more answers

Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A = {1, 3, 5, 7, 9}, B = {2, 4, 6, 8, 10}, and C = {1, 2, 4, 5, 8, 9}. List the element

Leto [7]

Answer:

$C\ n\ C^c = \{ \}$

$(A\ n\ C)^c = \{2,3,4,6,7,8,10\}$

$A\ u\ (B\ n\ C) = \{1, 2,3, 4,5, 7, 8,9\}$

Step-by-step explanation:

Required

Determine

$C\ n\ C^c$

$(A\ n\ C)^c$

$A\ u\ (B\ n\ C)$

Solving $C\ n\ C^c$

$C^c$ implies that elements in U but not in C

Since

$C = \{1, 2, 4, 5, 8, 9\}$

$C^c = \{3, 6, 7, 10\}$

$C\ n\ C^c = \{1, 2, 4, 5, 8, 9\}\ n\ \{3, 6, 7, 10\}$

$C\ n\ C^c = \{ \}$

<em>Because there's no intersection between both</em>

Solving $(A\ n\ C)^c$

First, we need to determine A n C

$A\ n\ C = \{1, 3, 5, 7, 9\}\ n\ \{1, 2, 4, 5, 8, 9\}$

$A\ n\ C = \{1, 5, 9\}$

$(A\ n\ C)^c = (\{1, 5, 9\})^c$

$(A\ n\ C)^c = \{2,3,4,6,7,8,10\}$

Solving $A\ u\ (B\ n\ C)$

First, we need to determine B n C

$B\ n\ C = \{2, 4, 6, 8, 10\}\ n\ \{1, 2, 4, 5, 8, 9\}$

$B\ n\ C = \{2, 4, 8\}$

So:

$A\ u\ (B\ n\ C) = \{1, 3, 5, 7, 9\}\ u\ \{2,4,8\}$

$A\ u\ (B\ n\ C) = \{1, 2,3, 4,5, 7, 8,9\}$

4 0

3 years ago

write a problem that can be modeled by the equation 2x+40=60 then sovle the equation and explain the solution in the context of

sergiy2304 [10]

2x + 40 = 60 (Subtract 40 from both sides)
- 40 - 40
--------------------------------
2x = 20 (Divide both sides)
2x/2 = 20/2
x = 10 (This is your final answer)

3 0

3 years ago