The answer is A:the body’s ability to be efficient during movement.
Answer:
Following are the program in the Python Programming language.
#define function
def negative_num(num_list):
#set list type variable
nlist=[]
#set the for loop
for n in num_list:
#check negative numbers
if(n<0):
#add the value of n in list
nlist.append(n)
#return list
return nlist
#set new list type variable that store list
newl=[-5,8,-6,3,-4,9,-7]
#print and call the function
print(negative_num(newl))
<u>Output</u>:
[-5, -6, -4, -7]
Explanation:
Here, we define the function "negative_num" and pass an argument "num_list" in its parameter and inside the function.
- Set new list data type variable "nlist".
- Set the for loop which iterate as the list.
- Set the if conditional statement to check the value of the list is less than 0 then, add that negative values in the variable "nlist".
- Then, return the new list.
Finally, we set a variable "newl" which store the list of negative and positive numbers then, we print and call the function.
Answer:
10%÷100 it is correct answer
The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.
Here is the starter code:
import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;
… (fill in other cases)
}
}
}
Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html
There might be a better way, but without loops or methods this is all I got.
