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Masja [62]
3 years ago
15

Abcd thank youuuuuuuuuu ​

Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

\frac{4x}{x-2}+\frac{7}{x-2}

Step-by-step explanation:

The general rule for add or subtracting fractions is that the fractions must have a common denominator, meaning that the value under the fraction bar must be the same. This rule is also applicable for algebraic fractions.

Therefore, when the question asks "Which of the following can be added without altering any of the fractions?", one should be looking for two fractions with a common denominator. Thus the answer would be the first option, which is the following;

\frac{4x}{x-2}+\frac{7}{x-2}

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Please help ASAP. Thanks so much
seropon [69]

Answer:

its A

Step-by-step explanation:

3 0
3 years ago
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Perform the indicated operations.<br> 5a/12bc times 18b^2 c^2/15a^3
Alexxx [7]
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3 0
3 years ago
X=y+1400<br> 0.08x+0.05=840
mezya [45]

Answer:

x = 7000

y = 5600

(7000, 5600)

Step-by-step explanation:

To solve the system of equations means to find the point of intersection (graphically). You are finding what value of 'x' and what value of 'y' fits both equations.

x = y + 1400

0.08x + 0.05y = 840

We can solve using the method <u>substitution</u>, where you replace a variable in one equation with an equivalent expression.

<u>Since "x" is y + 1400, we can replace "x" in the second equation.</u>

0.08x + 0.05y = 840

0.08(y + 1400) + 0.05y = 840    

Distribute over brackets by multiplying 0.08 with y, then 0.08 with 1400.

0.08y + 112 + 0.05y = 840         Collect like terms (with "y" variable)

112 + 0.13y = 840

Now isolate "y" in the simplified equation.

112 - 112 + 0.13y = 840 - 112         Subtract 112 from both sides

0.13y = 728

0.13y/0.13 = 728/0.13         Divide both sides by 0.13

y = 5600         Solved for y

We can substitute "y" with 5600 in any other equation that has "x".

x = y + 1400

x = 5600 + 1400          Add

x = 7000         Solved for x

You may express the answer as a coordinate, or an ordered pair (x, y).

The solution is (7000, 5600).

3 0
4 years ago
Read 2 more answers
write two numbers that when rounded to the greatest place value have an estimated sum of 11000 and an estimated difference of 30
Nookie1986 [14]

Answer:

First, we have rounded numbers A and B, and we know that:

A + B = 11000

A - B = 3000

Now we can solve this system of equations as:

Isolating one variable in one of the equations, i will choose A in the second equation:

A = 3000 + B.

Now we can replace this into the other equation:

3000 + B + B = 11000

2*B = 11000 - 3000 = 8000

B = 8000/2 = 4000

and:

A - 4000 = 3000

A = 3000 + 4000 = 7000.

But remember that our original numbers are not exactly whole numbers, they are rounded up, so we could write them as:

A = 6999.8 (that would be rounded up to 7000)

B = 3999.7 (that would be rounded up to 4000)

The sum is:

A + B = 10999.5 (notice that this would be rounded up to 11000)

A - B =  3000.1 (this would be rounded down to 3000)

7 0
3 years ago
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