3x^0 (2x^3y^2)^4
--------------------------
(4x^7y^4) ^2
= 3 * 1 (2x^3y^2)^4
-------------------------- Zero Exponent Property X^0 =1
(4x^7y^4) ^2
3 (2^4 *x^3*4 y^2*4)
-------------------------- power of a power property x^a ^b = x^(a*b)
4^2 x^7*2 y^4*2
3 *16 *x^12 y^8
-------------------------- simplify
16 x^14 y^8
3 *x^12 y^8
-------------------------- simplify
x^14 y^8
3 *x^(12-14) y^(8-8)
-------------------------- Quotient of Power X^a/ X^b = X^ (a-b)
3x^-2 y^0 simplify
3x^-2 *1 Zero Exponent Property X^0 =1
3 / x^2 Negative exponent property x^-a = 1/x^a
Step-by-step explanation:
first we notice that the line RS makes a diagonal in the circle.Since we are given ROP we can find SOP by:
180⁰-125⁰=55⁰
since they are in each others opposite point they are equal so that means that if we try the equation we did before: SOQ =ROP and QOR=SOP
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
<h3>What kind of polynomial does fit best to a set of points?</h3>
In this question we must find a kind of polynomial whose form offers the <em>best</em> approximation to the <em>point</em> set, that is, the least polynomial whose mean square error is reasonable.
In a graphing tool we notice that the <em>least</em> polynomial must be a <em>cubic</em> polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a <em>pseudo-linear</em> behavior.
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
To learn more on cubic polynomials: brainly.com/question/21691794
#SPJ1
It has to be 3 boxes for all of them to fit