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Rzqust [24]
3 years ago
8

Part A: A graph passes through the points (0, 4), (1, 8), and (2, 10). Does this graph represent a linear function or a non-line

ar function? Explain your answer in words.
Part B: Write one example of a linear function and one example of a non-linear function. (Use x and y as the variables) (10 points)
Mathematics
2 answers:
IRISSAK [1]3 years ago
4 0
Part A:  In (0,4) and (1,8), as x increases from 0 to 1, y increases from 4 to 8.  The slope of the line connecting these 2 pts. is (8-4) / (1-0), or 4.  Now do the same thing for the 2 pts (1,8) and (2, 10).  You will find that the slope in the 2nd case is different.  Thus, the 3 given pts do NOT lie on a straight line.  Function is non-linear.

Part B:  an example of a non-linear function would be y = 2x^2 - 5.  You can tell immediately from that exponent, 2, that this function is non linear.

An ex. of a linear function would include x to the 1st power only:  y = 3x - 7.
Artemon [7]3 years ago
4 0

Answer:  This is what i got hope it helps

Part A:  In (0,4) and (1,8), as x increases from 0 to 1, y increases from 4 to 8.  The slope of the line connecting these 2 points. is (8-4) / (1-0), or 4.  Now do the same thing for the 2 points (1,8) and (2, 10).  You will find that the slope in the 2nd case is different.  Thus, the 3 given points  do NOT lie on a straight line.  Function is non-linear.

Part B:  an example of a non-linear function would be y = 2x^2 - 5.  You can tell that the exponent, 2, that this function is non linear.

Step-by-step explanation:

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Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the
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Given:

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The nth term of the arithmetic sequence.

Solution:

We have,

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Here,

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Now, nth term  of an arithmetic sequence is

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Step-by-step explanation:

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Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa
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Answer:

x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

Step-by-step explanation:

We are given that a quadratic equation

x^2-x-1=0

We have to solve the equation by completing square and find the value of b.

(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0

(x-\frac{1}{2})^2-\frac{1}{4}-1=0

(x-\frac{1}{2})^2-\frac{1-4}{4}=0

(x-\frac{1}{2})-\frac{5}{4}=0

(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0

(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2

x-\frac{1}{2}=\frac{\sqrt5}{2} and x-\frac{1}{2}=-\frac{\sqrt5}{2}

x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}

And x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}

Therefore,x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

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