How to write 6,792,365 in expanded form

2 answers:

6 0

6x10 squared seven times,+ 7x10 squared six times, + 9x10 squared five times, + 2x10 squared four times, + 3x10 squared three times, + 6x10 squared two times, and 5x10 squared once. I'm sorry if this is wrong

VARVARA [1.3K]3 years ago

3 0

6,000,000+700,000+90,000+2,000+300+60+5

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Each snack at the concession stand is priced at $4.00. All of the snacks cost a total of $86.56. How many snacks will need to be

Nezavi [6.7K]

Answer:

Step-by-step explanation:

25*4=100 there for you need 25 snacks sold.

8 0

3 years ago

Hey can you please help me posted picture of question

AlekseyPX

We have the following function:
N (k):
Where, the indepent variable is k
The dependent variable is N
For the function:
k (n):
the independent variable is n
The dependent variable is k
Thus,
N (12) = 4
k (4) = 12
Answer:
TRUE
option A

8 0

3 years ago

What is the answer needdd it

Naddik [55]

I think it would be b or c

3 0

3 years ago

Martina needs to memorize words on a vocabulary list for German class. She has memorized 20 of the words, which is four-fifths o

tresset_1 [31]

Four fifths of 25 is 20 so the answer is 25

6 0

3 years ago

Read 2 more answers

BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!

mash [69]

Part 1:

Given that a store had 235 MP3 players in the month of January and that every month, 30% of the MP3 players were sold and 50 new MP3 players were stocked in the store.

The number of MP3 players in the store after the previous months sale is given by 0.7f(n - 1) and the number of MP3 players in the store after new MP3 were added is 0.7f(n - 1) + 50.

Therefore, the recursive function that best represents the number of MP3 players in the store f(n) after n months is given by f(n) = 0.7 x f(n − 1) + 50, f(0) = 235, n > 0

Part 2:

The average rate of change of a function from a to b is given by

$average \ rate \ of \ change= \frac{f(b)-f(a)}{b-a}$

Given that the equation showing the value of her investment after x years is given by

$f(x)=500(1.05)^x$

Thus, the average rate of change of the value of Sophia's investment from the second year to the fourth year is given by

$Average \ rate \ of \ change= \frac{f(4)-f(2)}{4-2} \\ \\ = \frac{500(1.05)^4-500(1.05)^2}{2} = \frac{607.75-551.25}{2} \\ \\ = \frac{56.5}{2} =28.25$

Therefore, the average rate of change of the value of Sophia's investment from the second year to the fourth year is 28.25 dollars per year.

7 0

3 years ago

Read 2 more answers