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bekas [8.4K]
3 years ago
8

Pls help 4/7+4/7x1/2

Mathematics
2 answers:
musickatia [10]3 years ago
8 0

Answer:

6/7 or .857

Step-by-step explanation:

It's called a calculator. Merry Christmas.

Georgia [21]3 years ago
5 0

Answer:

6/7

Step-by-step explanation:

4/7+4/7x1/2

4/7+2/7

=6/7

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Given: marked, PQ=8<br> PR=2x, TU=2z+3, ST=5z<br> Find: PR and ST
Ivenika [448]

Answer:

PR=8; ST=5

Step-by-step explanation:

Find PR:

PQ=PR

8=2x

x=4

PR=2x=2(4)=8

Find ST:

TU=ST

2z+3=5z

3=3z

z=1

ST=5z=5(1)=5

5 0
4 years ago
Work out 4/7 + 2 1/3
motikmotik

It's 61/21. That's the answer.

6 0
3 years ago
Geometry
satela [25.4K]

Answer:

Option (C)

Step-by-step explanation:

From the picture attached,

Two lines 'h' and 'k' are the parallel lines and a transversal 'n' is intersecting these parallel lines at two distinct points.

By the theorem of alternate interior angles, angle 8 and angle 11 will be equal in measure.

∠8 ≅ ∠11 [Alternate interior angles]

m(∠8) = m(∠11) = 118°

Therefore, Option (C) will be the answer.

7 0
3 years ago
Simplify the expression 3(m - 5) + m
adoni [48]

Answer:

<h2><u><em>4m -15</em></u></h2>

Step-by-step explanation:

simplify the expression 3(m - 5) + m

3 * (m - 5) + m =

3m - 15 + m

4m -15

7 0
3 years ago
How do I solve this
anastassius [24]
\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=&#10;\begin{cases}&#10;-7\\&#10;1&#10;\end{cases}&#10;\\\\\\&#10;\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}&#10;\\\\\\&#10;x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
4 years ago
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