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2 years ago

Which describes the relationship between 1 and 22?

Mathematics

1 answer:

devlian [24]2 years ago

7 0

Answer:

3rd circule

Step-by-step explanation:

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Please help me fast :)

liq [111]

Answer:

Step-by-step explanation:

Y = x² - 2x + 5

x = -2

y = -2² -2(-2) + 5

y = 4 + 4 + 5 = 13

x = -1

y = -1² -2(-1) + 5

y = 1 + 2 + 5 = 8

x = 1

y = 1² -2(1) + 5

y = 1 - 2 + 5 = 4

x = 3

y = 3² -2(3) + 5

y = 9 - 6 + 5 = 8

x = 6

y = 6² -2(6) + 5

y = 36 - 12 + 5 = 29

8 0

2 years ago

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

3 years ago

Josh estimates the height of his desk. what is the reasonable estimate?…

Ugo [173]

I cant answer if there is no info

5 0

2 years ago

دریافت رمزدوم کارت عابربانک ملت بهاره تبری

dolphi86 [110]

<span>Receive a reminder of the bank card for the people of the spring of Tabari?

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8 0

3 years ago

What is the coefficient of the c-term of the algebraic expression 14a -72r -c -34d?

8_murik_8 [283]

The coefficient C-term is 1 in problem. The coefficient is the number before the variable of said equation. Example, the coefficient of X for thus problem 4x-4y is 4 the number BEFORE the variable, never variable itself it won’t ever be 4x

3 0

2 years ago