1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brut [27]
3 years ago
10

How do you solve this problem in the photo?

Mathematics
2 answers:
Klio2033 [76]3 years ago
6 0

Answer: 5^2

Step-by-step explanation:

Since the base are all the same, you will add the exponents and let the exponents stay the same.

5^3  * 5^4= 5^7 * 5^-5= 5^2

Mashcka [7]3 years ago
6 0

Answer:

25

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

The rule can be extended to include more than 3 terms.

Given

5³ × 5^{4} × 5^{-5}

= 5^{(3+4-5)}

= 5²

= 25

You might be interested in
Property in equation. Find the value of n. 5+4= n+4
Nuetrik [128]
5+4 = n+4
9 = n+4
n = 5
4 0
3 years ago
What is a other name for the set of all x-values
Oliga [24]

Answer:

its domain

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Why can you use cross products to solve the proportion 18/5 equals x/100 for x?
blondinia [14]
18    x
--- = ----
5      100

18×100 = 5×x

1800 = 5x
-------    ----
   5          5

360 = x
Hope this helps!!!
5 0
3 years ago
Does anyone know how to solve this?
Lilit [14]

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

4 0
3 years ago
How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
Other questions:
  • Need help asap !!!!!
    5·2 answers
  • Each of the variables t, w, x, y, and z represents a different positive real number. Given the equations below, which of the 4 v
    9·1 answer
  • When adding two rational numbers,if a pair of addends has opposite signs ,then the sum will have the sign of the addenda with th
    6·1 answer
  • What is the factored form of the polynomial?
    12·1 answer
  • Find parametric equations for the line parallel to r=(6,-8) and passing through P(9,-1)
    13·1 answer
  • Complete factor of 12m+60
    11·1 answer
  • Aspirin is sold in boxes of 24 for $3.69, 50 for $5.49, 100 for $8.29, and 150 for $11.99. Which box has the best unit rate.
    14·1 answer
  • If a = 6, b= 7.5 and c= -2, calculate:<br> a + b + c
    15·2 answers
  • There are 23 teacher in a school. How many students are there in the school, in equivalent ratio​
    9·1 answer
  • Please help me with the questions please ASAP please please ASAP ASAP please ASAP
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!