We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
Answer:
9
Step-by-step explanation:
1, 3, 5, 9, 15, 19, 19
<span>(x – h)^2 + (y – k)^2 = r<span>^2
this equation is a derivative of the equation of a circle
x^2 + y^2 = r^2
This is from the origin. If we move the in x or y then the radius will change positions in x or y
with h = -3 and k = 1
we can plug in each set of numbers and solve.
we find Z to be on the circle edge!</span></span>
2011 because it has the higher gpa of all of them
Answer:
33.33%
Step-by-step explanation:
We need to calculate the <u>unit selling price and cost of each cosmetics.</u>
If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;
x = 1 cosmetic
since 360 = 12 cosmetic
cross multiply
12x = 360
x = 360/12
x = 30
Hence the unit cost price of the cosmetics will be Rs. 30
Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)
Selling price per unit = Rs. 40
Cost price per unit = Rs. 30
percent gain = SP-CP/CP * 100%
percent gain = 40-30/30 * 100
percent gain = 10/30 * 100
percent gain = 100/3
percent gain = 33.33%
Hence the percentage gain is 33.33%
