1 1/2 cups = 3/2. 3/2 divided by 4 = 3/2 x 1/4 = 3/8 cup
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
Step-by-step explanation:
First solve for y
given equation is 3x-2y ≥ 12
subtract 3x on both sides of the equation which would result with: -2y ≥ 12-3x
divide by -2 on both sides of the equation, flip the sign to ≤ because you are dividing by a negative, then you should get the result y<u> </u><u>≤</u><u> </u>-6 + 3x/2 (should look like a fraction)
y-intercept is at -6
slope is 3/2 (or three halves)
start at -6 on the y-axis, go up 3 across 2 and plot your point, keep repeating when going up and down the graph
Answer: A is correct
Step-by-step explanation: I took the test and I got 100
