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Airida [17]
3 years ago
8

​Triangles ABC​ and DFG are similar. Which proportion can be used to find the value of DG¯¯¯¯¯¯? 74=20DG 75=25DG 45=20DG 420=7DG

Two triangles A B C and D F G. A B is 4 feet. B C is 5 feet. A C is 7 feet. D F is 20 feet. F G is 25 feet. Angle B is congruent to angle F.

Mathematics
2 answers:
Tom [10]3 years ago
5 0
The correct answer would be B
lianna [129]3 years ago
3 0
I think is D. 74=20Dg
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I need help ASAP! I don’t understand this so I was hoping anyone would help
Pavel [41]
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Brainliest for whoever gets this right!
My name is Ann [436]

Answer:

x=\frac{(a^2+ab)}{a-b}

Step-by-step explanation:

So we want to make x the subject of the formula:

a(x-b)=a^2+bx

First, distribute the left side:

a(x)-a(b)=a^2+bx\\ax-ab=a^2+bx

Combine all the terms with x with it on one side. To do this, first subtract bx from both sides. The right side cancels:

(ax-ab)-bx=(a^2+bx)-bx\\ax-ab-bx=a^2

Remove the -ab from the left. Add ab to both sides. The left side cancels:

(ax-ab-bx)+ab=a^2+ab\\ax-bx=a^2+ab

Now, distribute out the x from the left side:

ax-bx=a^2+ab\\x(a-b)=a^2+ab

Divide both sides by (a-b). The left side cancels:

\frac{(x(a-b))}{a-b}=\frac{(a^2+ab)}{a-b}  \\x=\frac{(a^2+ab)}{a-b}

Therefore:

x=\frac{(a^2+ab)}{a-b}

5 0
3 years ago
Read 2 more answers
Find (f of f)(0) neeeed help ?
polet [3.4K]
So do you need help or are you asking people if they need help?
7 0
3 years ago
Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
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