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3 years ago

How do you solve this 2 step equation: 8+b/-4=5

1 answer:

3 0

I'm going to rewrite the equation assuming this is the correct form:
$8 - \frac{b}{4} = 5
\newline
-8 + 8 - \frac{b}{4} = 5 - 8
\newline
(-4)\cdot -\frac{b}{4} = -3 \cdot (-4)
\newline
b = -12$

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A scuba diver is swimming 15 feet below the water’s surface. The diver swims up slowly at 0.5 feet per second for 4 seconds; and

STatiana [176]

0.5 x 4 = 2 feet / 2 feet in 4 seconds
15 - 2 = 13
New depth: 13 feet

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13 - 1.2 = 11.8
New depth: 11.8 feet

8 0

3 years ago

Read 2 more answers

Which expressions are equivalent to -2y-8+4y

katrin2010 [14]

Answer:

2y-8

-Step-by-step explanation:

2y +4y = 2y

2y - 8

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3 years ago

A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is

Gnoma [55]

Answer:

<h2>29.4 length and 21.4 width.</h2>

Step-by-step explanation:

To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that W is the width and L the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this: $A_{total} = (L+6)(W+6)$ .

In addition, we know that the total area is 970 and the length is 8 ft longer than the width ( $L=W+8$ ). So:

$A_{total} = (L+6)(W+6)\\970 = (W+8+6)(W+6)\\970=W^{2}+20W+84\\W^{2}+20W-886=0$

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: $W_{1}=21.4$ and $W_{2}=-41.4$

Therefore, the width is 21.4 ft, because the negative number cannot represent distances.

Using the relation between length and width:

$L=W+8\\L=21.4+8=29.4$

Therefore, the dimensions of the pool are 29.4 length and 21.4 width.

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3 years ago

If 3y-x=-7 , what is the value of (2^x)/(8^y)

Travka [436]

Answer:

22=-7

Step-by-step explanation:

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3 years ago

PLZ HELP! Complete this proof. Given: a | | b Prove: ΔMOP ~ ΔRON

SashulF [63]

As shown in the given figure
line a // line b ⇒ given
MR and NP are transversals
So, for ΔMOP and ΔRON , we can conclude the following
(1) ∠1 = ∠2 ⇒⇒⇒ alternative angles are congruent
(2) ∠ MOP = ∠ RON ⇒⇒⇒ vertical angles are congruent
(3) ∠ 4 = ∠ 3 ⇒⇒⇒ alternative angles are congruent

So, from 1,2 and 3
∴ ΔMOP ~ ΔRON by AAA-Rule

6 0

3 years ago