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andreev551 [17]

3 years ago

7

Write and solve an inequality using the information about Noah.

2 answers:

gavmur [86]3 years ago

6 0

He cant wash 21 more

Otrada [13]3 years ago

5 0

Noah’s family can wash 21 or fewer loads of laundry before having to add more money to the card

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Is 3/4 greater than 3/5

Bas_tet [7]

Yes, 3/4 is equal to .75 and 3/5 is equal to .6

3 0

3 years ago

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What is the slope and y-intercept of the following equation:<br> = 13 − 4 (show your work pls)

Colt1911 [192]

Answer:

Slope is 1/3

Y intercept is -4

5 0

3 years ago

Boyd’s dartboard is octagonal. Each side measures 9 in. He drew a copy of the board that was smaller by a scale factor 0.25.

Basile [38]

<span>The question is about the side length of a copy of the dartboard. We know that the original dartboard has sides that measure 9 inches. We also have the scale factor 0.25. The ratio of the corresponding sides is called the scale factor. If we have the scale factor 0.25 it means that for 1 unit of the original figure there are 0.25 units of length of a copy. Therefore: x = 9 * 0.25; x = 2.25 in. Answer: The side length of the dartboard Boyd drew is 2.25 inches.</span>

5 0

3 years ago

Ace or expert pls help

jolli1 [7]

Answer:

Step-by-step explanation:

-0.25

-1/3

1/4

0.3

3 0

2 years ago

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Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

5 0

3 years ago