In triangle opq right angled at p op=7cm,oq-pq=1 determine the values of sinq and cosq
1 answer:
Answer:
see explanation
Step-by-step explanation:
let pq = x
given oq - pq = 1 then oq = 1 + x
Using Pythagoras' identity, then
(oq)² = 7² + x²
(1 + x)² = 49 + x² ( expand left side )
1 + 2x + x² = 49 + x² ( subtract 1 from both sides )
2x + x² = 48 + x² ( subtract x² from both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ⇒ pq = 24
and oq = 1 + x = 1 + 24 = 25 ← hypotenuse
sinq = =
cosq = =
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Answer:
There is 75% probability that Hanif will lose the game.
Step-by-step explanation:
Number of outcomes on tossing a coin = 2
Whenever an experiment is repeated "r" times, the total number of outcomes is calculated as:
Here n is the number of outcomes of one event. Since for tossing of a coin, the number of outcomes for each event is 2, so n = 2
The experiment is performed 3 times, so r = 3
Therefore, the total number of outcomes for tossing a coin 3 times is:
outcomes
Hanif wins if either of these two condition is met:
1) He gets all heads. There is only 1 outcome in 8 outcomes in which we can get all heads
2) He gets all tails. There is only 1 outcome in 8 outcomes in which we can get all tails.
Therefore, there are 2 possible outcomes for which Hanif will be the winner. On all other outcomes he will loose. Since total number of outcomes is 8, the number of outcomes for which Hanif will loose = 8 - 2 = 6 outcomes
We have to find the probability that Hanif will loose the game. Since, probability is defined as the ratio of desired outcomes to total number of outcomes, the probability that Hanif will loose the game will be:
Therefore, there is 75% probability that Hanif will lose the game.