In triangle opq right angled at p op=7cm,oq-pq=1 determine the values of sinq and cosq
1 answer:
Answer:
see explanation
Step-by-step explanation:
let pq = x
given oq - pq = 1 then oq = 1 + x
Using Pythagoras' identity, then
(oq)² = 7² + x²
(1 + x)² = 49 + x² ( expand left side )
1 + 2x + x² = 49 + x² ( subtract 1 from both sides )
2x + x² = 48 + x² ( subtract x² from both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ⇒ pq = 24
and oq = 1 + x = 1 + 24 = 25 ← hypotenuse
sinq = =
cosq = =
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Answer:
The remainder is zero
Step-by-step explanation:
To find the remainder we will use the long division
⇒(1)
⇒(2)
⇒(3)
From (1) , (2) and (3)
The quotient of the long division is and no remainder
So the remainder is zero
* If you want to check your answer Multiply the quotient by the divisor