Ex.
![2 {x}^{4} + 8 {x}^{3} + 4 {x}^{2} + 2 {x}^{2}](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B4%7D%20%20%2B%208%20%7Bx%7D%5E%7B3%7D%20%20%2B%204%20%7Bx%7D%5E%7B2%7D%20%20%2B%202%20%7Bx%7D%5E%7B2%7D%20)
This would be
![2 {x}^{2} ( {x }^{2} + 4x)(2 + 1)](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%28%20%7Bx%20%7D%5E%7B2%7D%20%20%2B%204x%29%282%20%2B%201%29)
How?
Group them
![(2 {x}^{4 } + 8 {x}^{3} )(4 {x}^{2} + 2 {x}^{2} )](https://tex.z-dn.net/?f=%282%20%7Bx%7D%5E%7B4%20%7D%20%20%20%2B%208%20%7Bx%7D%5E%7B3%7D%20%29%284%20%7Bx%7D%5E%7B2%7D%20%20%2B%202%20%7Bx%7D%5E%7B2%7D%20%29)
Make sure there is a GCF.
![2 {x}^{2} ( { x}^{2} + 4x)(2 + 1)](https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%28%20%7B%20x%7D%5E%7B2%7D%20%20%2B%204x%29%282%20%2B%201%29)
Hope this was clear
Using the power of zero property, we find that:
a) The simplification of the given expression is 1.
b) Since , equivalent expressions are: and .
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The power of zero property states that any number that is not zero elevated to zero is 1, that is:
Thus, at item a, , thus the simplification is .
At item b, equivalent expressions are found elevating non-zero numbers to 0, thus and .
The answer is #2 you’re welcome
2 1/2 + 2 3/5 =
2 5/10 + 2 6/10=
4 11/10 = 5 1/10
5 1/10 - 5 = 1/10
1/10 lb left over
Answer:
16 pots
Step-by-step explanation:
We first need to find out the amount of dirt that can be filled into a single flowerpot.
We use the formula to find the cylinder's volume.
π![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
![* h](https://tex.z-dn.net/?f=%2A%20h)
Height is equal to ten, Radius is equal to 7.
49π ![* 10](https://tex.z-dn.net/?f=%2A%2010)
≈ 1539.38
25,000 divided by 1539.38
≈ 16.24
He can fill 16 pots fully.