Answer:
too
Step-by-step explanation:
hhsihwhsusqioshsisjwk shshsusbsoosjs
To determine the number of days, we need to set up equations relating the given values above. The total distance that Kayla would want to travel is a sum of the total distance she traveled from running and the total distance she traveled from biking. So,
200 miles = (6 miles/day) x + (10 miles/day) y
where x is the number of days she spent running and y is the number of days she spent biking.
If the minimum days she used for biking would be 15 days or y = 15, then
200 miles = (6 miles/day) x + (10 miles/day) (15 days)
Solving for x,
200 = 6x + 150
50 = 6x
x = 8.3333 days
Total number of days = 15 days for biking + 8.3333 days for running = 23.3333 days or about 24 days.
Answer:
a. Domain: (-∞, ∞)
Range: (0,∞)
b. Domain: (-∞, ∞)
Range: (0,∞)
c. Domain: (-∞, ∞)
Range: (-∞,0)
d. Domain: (-∞, ∞)
Range: (-∞,0)
e. Domain: (-∞, ∞)
Range: (0,∞)
Step-by-step explanation:

These equations are all exponential functions. Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis unless a value has been added to it. If it has, the curve shifts. None of these have that and their y - values remain between 0 and ∞. This is the range, the set of y values.
However, the range of exponentials can change based on the leading coefficient. If it is negative the graph flips upside down and its range goes to -∞. C and D have this. Their range is (-∞, 0)
In exponential functions, the x values are usually not affected and all are included in the function. Their domain is (-∞, ∞). All of these equations have this domain.
a. Domain: (-∞, ∞)
Range: (0,∞)
b. Domain: (-∞, ∞)
Range: (0,∞)
c. Domain: (-∞, ∞)
Range: (-∞,0)
d. Domain: (-∞, ∞)
Range: (-∞,0)
e. Domain: (-∞, ∞)
Range: (0,∞)
1/5(25-5a)=4-a
⇔5-a=4-a
<span>NO SOLUTION</span>
<h3>Answer:</h3>
6 in
<h3>Explanation:</h3>
Let M be the midpoint of AB. ∆CMB and ∆CMA are both isosceles triangles, so CM = (AB)/2 = 9 in.
CG = (2/3)(CM) = (2/3)(9 in)
CG = 6 in
_____
<em>Comment on centroid and median</em>
The centroid of a triangle is located 1/3 the distance from the midpoint of a side to the opposite vertex. This is true for any median in any triangle. The proof can be developed from the fact that every median divides the triangle's area in half. Here, we just take advantage of this fact.