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3 years ago

3. (05.01) A consistent, dependent system of equations is a system with ______ (1 point)

Mathematics

2 answers:

ololo11 [35]3 years ago

6 0

Only one line yes yessssssssssdsssssssss

nevsk [136]3 years ago

5 0

Answer: only one line

Step-by-step explanation:

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Hey guys i suck at math and honestly tried this one for like ten minutes but I’m stuck please help me ill friend you and give fi

Afina-wow [57]

Answer:

2.6

Step-by-step explanation:

if you need me to explain it let me know and I will.

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3 years ago

If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun

saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

$P(t)=181843(1.04)^{(\frac{t}{10})}$

where, P(t) is population after t years.

At t=5,

$P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20$

At t=6,

$P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95$

At t=7,

$P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57$

At t=8,

$P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06$

At t=9,

$P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44$

At t=10,

$P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72$

The rate of change of P(t) on the interval $[x_1,x_2]$ is

$m=\frac{P(x_2)-P(x_1)}{x_2-x_1}$

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

$m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504$

The average rate of change of the population on the intervals [ 5 , 9 ] is

$m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06$

The average rate of change of the population on the intervals [ 5 , 8 ] is

$m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62$

The average rate of change of the population on the intervals [ 5 , 7 ] is

$m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185$

The average rate of change of the population on the intervals [ 5 , 6 ] is

$m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75$

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

7 0

4 years ago

If a temperature in degrees Celsius is given as C, finding the sum of 1.8 times C and 32 gives the temperature in degrees Fahren

Yuki888 [10]

Answer:

hsuvsjvBcsjfbdkchdkksfsnadeolataogzfdkgcjb

6 0

3 years ago

Lori buys a $1500 certificate of deposit (CD) that earns 6% interest that compounds monthly. How much will the CD be worth in:

goldfiish [28.3K]

Answer:

Money = (1500)e^(0.06t)

t = num of months

Money = Money at end of that tiem period

5 0

3 years ago

Read 2 more answers

1. How many ways are there to make an octagon with 19 different sticks when order DOESN’T matter?

Oksanka [162]

Answer:

1. 75582

2. 3047466240

Step-by-step explanation:

1. If order does not matter, this is a combination problem. You are choosing 8 sticks from a set of 19. (Octagons have 8 sides.)

The formula for combinations of n things chosen r at a time "n choose r" is

$_nC_r = \frac{n!}{r!(n-r)!}$

$_19C_8=\frac{19!}{8!(19-8)!} = \frac{19!}{8!11!}=75582$

2. If order matters, there are more possibilities. This is a permutation problem. The number of permutations of 19 things taken 8 at a time, "19 permute 8" is

$_nP_r=\frac{n!}{(n-r)!} \\ _{19}P_8=\frac{19!}{(19-8)!} = 3047466240$

6 0

3 years ago