Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
Answer:
10 feet
Step-by-step explanation:
Given that the distance to be reached is 8 feet above ground and she she placed a ladder so that it reached the bottom of the window, the base of the ladder was 6 feet from the house, the length of the ladder considered with the other lengths forms a right angled triangle.
The length of the ladder represents the hypotenuse side hence using pythagoras theorem
F^2 = 8^2 + 6^2
where F is the length of the ladder in feet
F^2 = 64 + 36
= 100
find the root of both sides
F = 10 feet
The ladder is 10 feet long
The correct answer for the question shown above is the second option, the option B, which is: B. <span>W'(2, 10), X'(2, 2), Y'(10, 2)
The explanation is shown below: As you can see, the original triangle has the following coordinates </span><span> W(1, 5), X(1, 1), and Y(5, 1); the triangle must be dilated by a common scale factor, so if you analize the option B, you can notice that the triangle was dilated by a scale factor of 2.</span>
Answer:
B
Step-by-step explanation:
All of the other answers are wrong im right believe me i know I am