Answer:
Step-by-step explanation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
Given:
300
g
of
C
l
2
300
g
of
K
B
r
(a) Mass of
C
l
2
= 300g
Molecular mass of
C
l
2
= 2(35.45) = 70.906 g
/
m
o
l
No.of moles of
C
l
2
=
m
a
s
s
/
m
o
l
a
r
m
a
s
s
=
300
/
70.906
=
4.23
moles
Mass of
K
B
r
=
300
g
Molar mass of
K
B
r
=
39
+
79.9
=
118.9
g
/
m
o
l
No.of moles of
K
B
r
=
300
/
118.9
=
2.52
moles
Now,
Consider the equation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
1
mole of
C
l
2
= 2 moles of
K
C
l
4.23
moles of
C
l
2
= 2x4.23=
8.46
moles
2
moles of
K
B
r
= 2 moles of
K
C
l
2.52
moles of
K
B
r
=
2.52
moles
Now convert moles to mass,
Mass of
K
C
l
produced by
C
l
2
=
8.46
×
70.906
=
599.8
g
Mass of
K
C
l
produced by potassium bromide =
2.52
×
74.5
=
187.74
g
The dummies pin code would be 49.36.
Answer:
x=1/2
Step-by-step explanation:
-5(x - 4) + 6 = 5(3x+4) -4
WE APPLY DISTRIBUTIVE PROPERTY:
-5*x +5*4 + 6 = 5*3x +5*4 -4
-5x + 26 = 15x +20 -4
26 +4 -20=15x+5x
10=20x
x= 10/20
we have:
x=1/2
.363636 as a fraction is 4/11
