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solmaris [256]
4 years ago
13

Mark used a graph to compare wages from two restaurant jobs. A dishwasher earns 7.25 dollars per hour, while a waiter earns 3.75

dollars per hour in addition to 25 dollars per day. To the nearest hour, when will the two jobs earn the same amount? What will the amount be when the two jobs earn the same amount? Round to the nearest.

Mathematics
1 answer:
BARSIC [14]4 years ago
5 0
I would say $52 because if you say 50 it would be wrong because the lines don't meet exactly on 50
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A $25 credit and a $25 charge appear similar, yet they are very different.
lorasvet [3.4K]

Answer:

Similarities:

  • Both transactions have a magnitude of $25.
  • Both transactions result in a change of $25 in the account.
  • The absolute value is the same ($25).

Differences:

  • The two transactions yield opposite results.

Step-by-step explanation:

A $25 credit results in a positive action in the account while the $25 charge is a negative action on the account.

3 0
3 years ago
All you need is in the photo <br>please answer fast ​
Mashutka [201]

Answer:

12 ounces

Step-by-step explanation:

Answer above.

4 0
3 years ago
The sum of three consecutive multiples of 7 is 777 find these multiples
Rudik [331]

let the consecutive multiples be 7(n-1) , 7n and 7(n+1)

so 7(n-1)+7n+7(n+1)=777

or 3n=111,

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4 0
3 years ago
Read 2 more answers
Sabra joins a cooking club for $8.50 and pays $6.25 each month. She also joins a movie club for $12 and pays $3.75 each month. W
podryga [215]

Simplified expression for total amount spent is 10(2.05 + m)

Step-by-step explanation:

  • Step 1: Write expression for expense on joining cooking club for m months.

Expense = 8.50 + 6.25 × m

  • Step 2: Write expression for expense on joining movie club for m months.

Expense = 12 + 3.75 × m

  • Step 3: Calculate the total amount spent on both clubs

Total Amount = 8.50 + 6.25m + 12 + 3.75m = 20.5 + 10m = 10(2.05 + m)

6 0
3 years ago
Question 7 of 10
Ganezh [65]

Answer:

  • Option B

Step-by-step explanation:

Given Equation :

\qquad \sf \dashrightarrow \: 3(4x+3) = 2x - 5(3 - x) + 2

Using distribute property:

\qquad \sf \dashrightarrow \: 12x + 9 = 2x - 15 + 5x + 2

Adding the like terms we get :

\qquad \sf \dashrightarrow \: 12x + 9 = 2x  + 5x  - 15 + 2

\qquad \sf \dashrightarrow \: 12x + 9 = 7x  - 13

Transposing the variables on the right side and constant terms on the left side :

\qquad \sf \dashrightarrow \: 12x  - 7x =   - 13 - 9

\qquad \sf \dashrightarrow \: 5x =   - 22

Dividing both sides by 5 :

\qquad \sf \dashrightarrow \:  \dfrac{5x}{5}  =  \dfrac{ - 22}{5}

\qquad \bf \dashrightarrow \:  x =  \dfrac{ - 22}{5}

3 0
3 years ago
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