Question 7 of 10

Mathematics

1 answer:

Ganezh [65]2 years ago

3 0

Answer:

Option B

Step-by-step explanation:

Given Equation :

$\qquad \sf \dashrightarrow \: 3(4x+3) = 2x - 5(3 - x) + 2$

Using distribute property:

$\qquad \sf \dashrightarrow \: 12x + 9 = 2x - 15 + 5x + 2$

Adding the like terms we get :

$\qquad \sf \dashrightarrow \: 12x + 9 = 2x + 5x - 15 + 2$

$\qquad \sf \dashrightarrow \: 12x + 9 = 7x - 13$

Transposing the variables on the right side and constant terms on the left side :

$\qquad \sf \dashrightarrow \: 12x - 7x = - 13 - 9$

$\qquad \sf \dashrightarrow \: 5x = - 22$

Dividing both sides by 5 :

$\qquad \sf \dashrightarrow \: \dfrac{5x}{5} = \dfrac{ - 22}{5}$

$\qquad \bf \dashrightarrow \: x = \dfrac{ - 22}{5}$

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