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2 years ago

Question 7 of 10

Mathematics

1 answer:

Ganezh [65]2 years ago

3 0

Answer:

Option B

Step-by-step explanation:

Given Equation :

$\qquad \sf \dashrightarrow \: 3(4x+3) = 2x - 5(3 - x) + 2$

Using distribute property:

$\qquad \sf \dashrightarrow \: 12x + 9 = 2x - 15 + 5x + 2$

Adding the like terms we get :

$\qquad \sf \dashrightarrow \: 12x + 9 = 2x + 5x - 15 + 2$

$\qquad \sf \dashrightarrow \: 12x + 9 = 7x - 13$

Transposing the variables on the right side and constant terms on the left side :

$\qquad \sf \dashrightarrow \: 12x - 7x = - 13 - 9$

$\qquad \sf \dashrightarrow \: 5x = - 22$

Dividing both sides by 5 :

$\qquad \sf \dashrightarrow \: \dfrac{5x}{5} = \dfrac{ - 22}{5}$

$\qquad \bf \dashrightarrow \: x = \dfrac{ - 22}{5}$

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18. In the figure, o is the center of the circle passing through P, Q, R and S. If angle SOQ = 150°, find the values of x and y.

AveGali [126]

Answer:

x = 75°

y = 105°

Step-by-step explanation:

Angle subtended on the circumference of the circle is half of the angle subtended on the center of the circle.

$\therefore m\angle SRQ = \frac{1}{2} \times m\angle SOQ\\\\\therefore x = \frac{1}{2} \times 150\degree \\\\\red{\bold{\therefore x =75\degree}} \\$

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2 years ago

A line that passes through the points (2,7) and (6,15)<br> Show work.

s2008m [1.1K]

Answer:

The equation of the line is y = 2x + 3

Step-by-step explanation:

In order to find this, we first need to find the slope. For that we use slope intercept form.

m(slope) = (y2 - y1)/(x2 - x1)

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3 years ago

What is the minimum value for z = -x + 3y over the feasibility region defined by the constraints shown above?

natima [27]

Answer:

The minimum value for $z=-x+3y$ over the feasibility region is -1.

Step-by-step explanation:

Given conditions:

The function $z=-x+3y$

Subject to the following constraint

$x\geq 1$

$x\leq 7$

$y\geq 2$

$y\leq \frac{-1}{3}x+6$

Graph the region correspond to the solution of the system of constraints as given below.

Now, from the graph we have the coordinates of the vertices of the region formed.

The vertices are $(1,2)$ , $(7,2)$ , $(1,5.667)$ and $(7,3.667)$ .

now, evaluate the function $z=-x+3y$ at each vertex.

At $(1,2)$ ,

$z=-1+3\cdot 2=-1+6=5$

At $(7,2)$ ,

$z=-7+3\cdot 2=-7+6=-1$

At $(1,5.667)$

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At $(7,3.667)$

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