Question

What are the zeros of the function? g(x)=x2−x−72

Answer 1

Alright, lets get started.

The given function is $x^2 - x - 72$.

For finding its zeros, we need to first factor this function and then set it equal to zero.

$x^2 - x -72$

$(x-9)(x+8)= 0$

$(x-9) = 0$

$x = 9$

$(x+8) = 0$

$x = -8$

Hence the zeros are 9 and -8 of given function. : Answer

Hope it will help :)

Answer 2

It's possible for it to be factored after factoring set both numbers equal to 0 and solve and you should get 9 and -8