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anygoal [31]
3 years ago
14

Last season Ellen and Janet together won 32 tennis matches Ellen won 6 more than then Janet How many more matches did Ellen win

Mathematics
2 answers:
joja [24]3 years ago
8 0

T = J + E

T = J + (J + 6)

T = 32

32 = 13 + (13 + 6)

32 = 13 + 19

32 = 32

Ellen won 19 matches.

ki77a [65]3 years ago
7 0

Answer:

19 matches which is 6 more than Janet’s

Step-by-step explanation:

Let the matches won by Ellen be A and Janet be B

Given they both won 32 matches

That’s

A + B = 32

And Ellen won 6 more than Janet

That’s

A = 6 + B

So we now have two equations

1. A + B = 32

2. A = 6 + B

Substitute B + 6 for A in the first equation

We have

A + B = 32

6 + B + B = 32

6 + 2B = 32

Subtract 6 from both sides

6 - 6 + 2B = 32 - 6

2B = 26

Divide both sides by 2

2B/2 = 26/2

B = 13

Recall

A = 6 + B

Therefore

A = 6 + 13

A = 19

Ellen won 19 matches which is 6 more than Janet’s

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The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

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Now, let's square both sides.

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Subtract 400 from both sides.

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Factor

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Set both terms equal to zero and solve.

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Let's plug 28/5 into our length equation.

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In conclusion,

Length = 96/5 inches

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