<span>Both variables are categorical. We analyze an association through a comparison of conditional probabilities and graphically represent the data using contingency tables. Examples of categorical variables are gender and class standing.</span>
According to Greg himself (probably a master at pies) says perfect cherry pies have a ratio of 240 cherries to 3 pies. First, we need to divide 240 cherries by 3 pies to find out how many cherries are in one pie.
240 / 3 = 80
Then multiply by 9 to get your answer.
9 * 80 = 720
Answer:
A) 150 m
B) 180.28 m
Step-by-step explanation:
A) In order to find the horizontal distance from the base of the cliff to the speed boat, use the Pythagorean theorem to calculate the length of the missing side.
We are told that one of the sides is 80 m and the hypotenuse is 170 m. Therefore,
- a² + b² = c²
- (80)² + b² = (170)²
- b² = 170² - 80²
- b² = 22500
- b = 150
The horizontal distance between the base of the cliff and the boat is 150 m.
B) Now, the side that was 80 m is now 100 m (includes the height that the helicopter is above Jumbo). The horizontal distance remains the same, 150 m, but the hypotenuse is different. Solving for the hypotenuse will give us the distance between the helicopter and the speed boat.
- (100)² + (150)² = c²
- 32500 = c²
- 180.28 = c
The distance between the helicopter and the speed boat is 180.28 m.
Answer:
Combine the like terms. In this equation there are two like terms. They both are xy. Note: When there is no number in front of a term, you can assume that the number is 1.
5xy - 1xy
Subtract normally and then attach the xy.
4xy
Hope this helps! :)
Check the picture below.
so the <u>triangular prism</u> is really 3 rectangles and two triangles stacked up to each other at the edges, so if we simply get the area of each figure individually and sum them up, that's the area of the prism.
let's notice, the triangles have a base of 2.4 and a height/altitude of 1.
![\bf \stackrel{\textit{2 triangles's area}}{2\left[ \cfrac{1}{2}(2.4)(1) \right]}~~+~~\stackrel{\textit{right rectangle}}{(2\cdot 1.5)}~~+~~\stackrel{\textit{left rectangle}}{(2\cdot 1.7)}~~+~~\stackrel{\textit{bottom rectangle}}{(2\cdot 2.4)} \\\\\\ 2.4+3+3.4+4.8\implies 5.4+8.2\implies 13.6](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B2%20triangles%27s%20area%7D%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.4%29%281%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bright%20rectangle%7D%7D%7B%282%5Ccdot%201.5%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bleft%20rectangle%7D%7D%7B%282%5Ccdot%201.7%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bbottom%20rectangle%7D%7D%7B%282%5Ccdot%202.4%29%7D%20%5C%5C%5C%5C%5C%5C%202.4%2B3%2B3.4%2B4.8%5Cimplies%205.4%2B8.2%5Cimplies%2013.6)
