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yan [13]
3 years ago
7

Anyone up for the question, prize awaits you

Mathematics
1 answer:
Vikki [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Are there any answer choices?

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In the right triangle shown, A= 30° and AB = 8.
zloy xaker [14]

Answer:

BC=4\ units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

sin(30^o)=\frac{BC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

we have

AB=8\ units\\\\sin(30^o)=\frac{1}{2}

solve for BC

BC=sin(30^o)(AB)

substitute the values

BC=(\frac{1}{2})(8)

BC=4\ units

4 0
3 years ago
ВС<br> Round your answer to the nearest hundredth.<br> B.<br> ?<br> 35°<br> A<br> 2.<br> с
Akimi4 [234]

Answer:

a diagram is necessary. please provide a diagram.

6 0
3 years ago
Hassan made a vegetable salad with 2 3/8 pounds of tomatoes, 1 1/4 pounds of asparagus, and 2 7/8 pounds of potatoes. How many p
faltersainse [42]

Step-by-step explanation:

OK so

Tomatoes = 2 3/8 = 19/8 (turned into improper fraction)

Asparagus = 1 1/4 =5/4

Potatoes = 2 7/8 = 23/8

Total vegetables used =

19/8 + 5/4 + 23/8 = 42/8 + 5/4 = 42+10/8 =52/8

Answer is 52/8 = 6.5

<u>Answer :</u><u> </u><u>52</u><u>/</u><u>8</u><u> </u><u>pounds</u><u> </u><u>were</u><u> </u><u>used</u><u> </u><u>altogether</u>

3 0
2 years ago
Read 2 more answers
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
Can someone help me and find x
Anettt [7]

Answer:

x=-7

Step-by-step explanation:

2x-5=5x+16

(2x-5x)=(5+16)

-3x=21

21/(-3)=-7

5 0
3 years ago
Read 2 more answers
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